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7m^2+20m-75=0
a = 7; b = 20; c = -75;
Δ = b2-4ac
Δ = 202-4·7·(-75)
Δ = 2500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2500}=50$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-50}{2*7}=\frac{-70}{14} =-5 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+50}{2*7}=\frac{30}{14} =2+1/7 $
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